The Russian Andrey Rublev ended the dream of the Czech Jiri Vesely, revelation of the competition, after winning the final 6-3 and 6-4 and winning the Dubai ATP 500 title, the second this year and the tenth of his career.
Vesely, who one by one left the Spanish Roberto Bautista, the Serbian Novak Djokovic and the Canadian Denis Shapovalov on the way to the tournament, could not beat Rublev, who has now accumulated nine wins in a row.
The Muscovite adds Dubai to Marseille from where he emerged victorious a week ago. The seventh player in the world took an hour and twenty minutes to resolve the confrontation against the former junior world number one and champion of the Australian Open in this category.
The Czech, however, did not give any ease to a rival with whom he was facing for the first time. Rublev broke the Czech in the fourth game of the first set to establish a 3-1 lead that he was unable to balance.
More solvent was shown in the second. Although he lost his serve in the opening set, he managed to break the Russian and level the set at three. But Rublev accelerated, broke again and took the victory that eluded the Czech, who will return next week among the top one hundred in the world but is still anchored in the two titles he has accumulated since he won in Pune in 2020.
